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Analysis of Copper Sulphate (CuSO₄)

Class 12 Chemistry Practical

Aim

To analyse the given inorganic salt for one acidic and one basic radical.

Preliminary Test

ExperimentObservationInference
Physical examinationBlue crystalline solid (blue vitriol); odourlessCu²⁺ present, not a white salt
SolubilitySoluble in water giving a blue solutionHydrated Cu²⁺ ions
Dry heatingWater lost; residue white anhydrous CuSO₄, then black CuO on strong heatingHydrated copper sulphate
Flame testBluish-green flameCopper indicated
Dilute H₂SO₄No CO₂Not carbonate
Conc. H₂SO₄No halide / NO₂ fumesAnion is sulphate, not nitrate / halide

Test of Anion (SO₄²⁻)

ExperimentObservationInference
Confirmatory Tests
Barium chloride
Acidify the water / soda extract with dilute HCl and add BaCl₂
White ppt of BaSO₄, insoluble in conc. HCl and conc. HNO₃SO₄²⁻ is confirmed
Lead acetate
Acidify with acetic acid and add lead acetate
White ppt of PbSO₄SO₄²⁻ is confirmed

Ionic equations

  • Ba²⁺ + SO₄²⁻ → BaSO₄ ↓ (white, insoluble in acids)
  • Pb²⁺ + SO₄²⁻ → PbSO₄ ↓

Test of Cation (Cu²⁺)

ExperimentObservationInference
Pass H₂S through the original solution acidified with dilute HClBlack ppt of CuSGroup II (Cu²⁺) may be present
Confirmatory Tests
Ammonium hydroxide
Dissolve the ppt in dilute HNO₃. Add NH₄OH dropwise, then in excess
Pale blue ppt dissolves giving a deep blue [Cu(NH₃)₄]²⁺ solutionCu²⁺ is confirmed
Potassium ferrocyanide
Acidify with acetic acid and add K₄[Fe(CN)₆]
Chocolate-brown ppt of copper ferrocyanideCu²⁺ is confirmed

Ionic equations

  • Cu²⁺ + H₂S → CuS ↓ (black) + 2H⁺
  • Cu(OH)₂ + 4NH₄OH → [Cu(NH₃)₄]²⁺ (deep blue) + 2OH⁻ + 4H₂O
  • 2Cu²⁺ + [Fe(CN)₆]⁴⁻ → Cu₂[Fe(CN)₆] ↓ (chocolate-brown)

Result

The given salt contains Cu²⁺ as the cation (basic radical) and SO₄²⁻ as the anion (acidic radical). The salt is Copper Sulphate (CuSO₄).

Precautions

  1. Use small quantities of salt and reagents; do not use excess.
  2. Keep the mouth of the test tube away from the face while heating.
  3. Use freshly prepared FeSO₄ for the brown ring test.
  4. Nessler’s reagent is toxic (mercury); handle with care and do not pipette by mouth.

Viva voce

  1. Why is the salt blue?

    [Cu(H₂O)₆]²⁺ absorbs in the orange-red and appears blue.

  2. Why black ppt with H₂S?

    CuS is very insoluble and black.

  3. Why H₂S in acidic medium?

    Group II sulphides ppt even at low [S²⁻]; ZnS would not.

  4. Why deep blue with excess NH₃?

    Formation of [Cu(NH₃)₄]²⁺.

  5. Why chocolate-brown ferrocyanide?

    Copper ferrocyanide. Zinc ferrocyanide is bluish-white.

  6. Why BaCl₂?

    Sulphate anion.

  7. What is blue vitriol?

    CuSO₄·5H₂O.

  8. Why does anhydrous CuSO₄ turn white?

    Loss of water of crystallisation; used as a test for water.